{"id": "chat-17004c8f34e947818a7669887971907e", "object": "chat.completion", "created": 1737099789, "model": "Qwen2.5-0.5B-Instruct", "choices": [{"index": 0, "message": {"role": "assistant", "content": "答案是B。当采用分块查找时,数据分成若干块,每块内数据不必有序,但块间必须有序,每块内最大(或最小) 的数据组成索引块。", "tool_calls": []}, "logprobs": null, "finish_reason": "stop", "stop_reason": null}], "usage": {"prompt_tokens": 184, "total_tokens": 229, "completion_tokens": 45}, "prompt_logprobs": null, "model_spec": {"api_url": "http://127.0.0.1:8801/v1/chat/completions", "model_id": "Qwen2.5-0.5B-Instruct", "api_key": "EMPTY"}, "answer_id": "answer-b0a2db0a1dc4f1e61ccf0f38e2586828", "subset_name": "college_programming", "raw_input": {"id": 0, "question": "当采用分块查找时,数据的组织方式为____", "A": "数据分成若干块, 每块内数据有序", "B": "数据分成若干块, 每块内数据不必有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块", "C": "数据分成若干块, 每块内数据有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块", "D": "数据分成若干块, 每块( 除最后一块外) 中数据个数需相同", "answer": "B", "explanation": ""}, "origin_prompt": {"data": ["以下是中国关于大学编程考试的单项选择题,请选出其中的正确答案。\n问题:当采用分块查找时,数据的组织方式为____\nA. 数据分成若干块, 每块内数据有序\nB. 数据分成若干块, 每块内数据不必有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块\nC. 数据分成若干块, 每块内数据有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块\nD. 数据分成若干块, 每块( 除最后一块外) 中数据个数需相同\n答案: "], "multi_choices": ["A", "B", "C", "D"], "raw_input": {"id": 0, "question": "当采用分块查找时,数据的组织方式为____", "A": "数据分成若干块, 每块内数据有序", "B": "数据分成若干块, 每块内数据不必有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块", "C": "数据分成若干块, 每块内数据有序, 但块间必须有序, 每块内最大( 或最小) 的数据组成索引块", "D": "数据分成若干块, 每块( 除最后一块外) 中数据个数需相同", "answer": "B", "explanation": ""}}} {"id": "chat-175303222c0048e99962249c403478c2", "object": "chat.completion", "created": 1737099789, "model": "Qwen2.5-0.5B-Instruct", "choices": [{"index": 0, "message": {"role": "assistant", "content": "在实现一个银行系统时,最恰当的资源组合方式是D. 实例化。通过实例化,我们可以创建一个具体的银行系统实例,包括存钱、取钱和转账等功能。这种方式可以确保每个功能都有一个独立的实现,从而提高系统的可维护性和可扩展性。其他选项如继承和重载虽然可以实现功能的封装和重用,但它们通常不适用于创建完整的银行系统实例。", "tool_calls": []}, "logprobs": null, "finish_reason": "stop", "stop_reason": null}], "usage": {"prompt_tokens": 100, "total_tokens": 192, "completion_tokens": 92}, "prompt_logprobs": null, "model_spec": {"api_url": "http://127.0.0.1:8801/v1/chat/completions", "model_id": "Qwen2.5-0.5B-Instruct", "api_key": "EMPTY"}, "answer_id": "answer-6c52a33aebfd7983a128a3103dc65c49", "subset_name": "college_programming", "raw_input": {"id": 1, "question": "实现一个银行系统,包括存钱、取钱、转账等多项业务,最恰当的资源组合方式是____", "A": "继承", "B": "重载", "C": "组合", "D": "实例化", "answer": "C", "explanation": ""}, "origin_prompt": {"data": ["以下是中国关于大学编程考试的单项选择题,请选出其中的正确答案。\n问题:实现一个银行系统,包括存钱、取钱、转账等多项业务,最恰当的资源组合方式是____\nA. 继承\nB. 重载\nC. 组合\nD. 实例化\n答案: "], "multi_choices": ["A", "B", "C", "D"], "raw_input": {"id": 1, "question": "实现一个银行系统,包括存钱、取钱、转账等多项业务,最恰当的资源组合方式是____", "A": "继承", "B": "重载", "C": "组合", "D": "实例化", "answer": "C", "explanation": ""}}} {"id": "chat-697dc6566fe2405fa6e90b4c477dc04c", "object": "chat.completion", "created": 1737099790, "model": "Qwen2.5-0.5B-Instruct", "choices": [{"index": 0, "message": {"role": "assistant", "content": "程序运行的结果是:\n\nB. 1/10/2002 10/10/2002\n\n在C++中,`date`类的构造函数`date(int x, int y, int z)`接受三个整数参数,用于初始化日期。在`main`函数中,我们创建了两个`date`对象`day1`和`day2`,并分别设置了它们的属性。然后,我们调用了`day1.set()`和`day2.display()`方法来显示日期。由于`day1`和`day2`的构造函数参数分别是1和10,所以它们的日期是1月10日和10月10日。因此,最终的输出是:\n\n1/10/2002 10/10/2002", "tool_calls": []}, "logprobs": null, "finish_reason": "stop", "stop_reason": null}], "usage": {"prompt_tokens": 268, "total_tokens": 449, "completion_tokens": 181}, "prompt_logprobs": null, "model_spec": {"api_url": "http://127.0.0.1:8801/v1/chat/completions", "model_id": "Qwen2.5-0.5B-Instruct", "api_key": "EMPTY"}, "answer_id": "answer-f4a8f2acd4101e3ef96f44c7747cd844", "subset_name": "college_programming", "raw_input": {"id": 2, "question": "#include\nclass date\n{\nprivate:\nint day,month,year;\npublic:\ndate(){}\ndate(int x,int y,int z){day=x;month=y,year=z;}\nvoid set(){day=1;month=10;year=2002;}\nvoid display(){cout<\nclass date\n{\nprivate:\nint day,month,year;\npublic:\ndate(){}\ndate(int x,int y,int z){day=x;month=y,year=z;}\nvoid set(){day=1;month=10;year=2002;}\nvoid display(){cout<\nclass date\n{\nprivate:\nint day,month,year;\npublic:\ndate(){}\ndate(int x,int y,int z){day=x;month=y,year=z;}\nvoid set(){day=1;month=10;year=2002;}\nvoid display(){cout<\nusing namespace std;\n\nclass integer {\npublic:\n integer(int value=0):value(value) {}\n integer operator+(integer itg) {\n return value += itg.value;\n }\n friend ostream& operator<<(ostream& os, integer& it) {\n return os << it.value;\n }\nprivate:\n int value;\n};\n\nint main() {\n integer i;\n integer ii;\n ii = 2 + i;\n cout << \"i=\" << i << \", ii=\" << ii << endl;\n return 0;\n}\n```\n\n在编译时,程序会报错,因为 `integer` 类的构造函数 `integer(int value=0)` 和 `operator+(integer itg)` 都没有定义。在运行时,程序会输出 `i=0, ii=2`,因为 `ii` 的值是 `2 + i` 的结果,即 `2 + 2`,所以 `ii` 的值是 `2`。\n\n因此,正确答案是:\n\nA. i=0, ii=2", "tool_calls": []}, "logprobs": null, "finish_reason": "stop", "stop_reason": null}], "usage": {"prompt_tokens": 201, "total_tokens": 492, "completion_tokens": 291}, "prompt_logprobs": null, "model_spec": {"api_url": "http://127.0.0.1:8801/v1/chat/completions", "model_id": "Qwen2.5-0.5B-Instruct", "api_key": "EMPTY"}, "answer_id": "answer-5c5d87d2b250f8f512a5946b30268376", "subset_name": "college_programming", "raw_input": {"id": 4, "question": "有以下程序代码\n#include\nusing namespace std;\nclass integer{\npublic:\ninteger(int value=0):value(value){}\ninteger operator+(integer itg){\nreturn value+=itg.value;\n}\nfriend ostream&operator<<(ostream&os,integer&it){\nreturn os<\nusing namespace std;\nclass integer{\npublic:\ninteger(int value=0):value(value){}\ninteger operator+(integer itg){\nreturn value+=itg.value;\n}\nfriend ostream&operator<<(ostream&os,integer&it){\nreturn os<\nusing namespace std;\nclass integer{\npublic:\ninteger(int value=0):value(value){}\ninteger operator+(integer itg){\nreturn value+=itg.value;\n}\nfriend ostream&operator<<(ostream&os,integer&it){\nreturn os<\nclass vehicle{\nprotected:\nint wheels;\npublic:\nvehicle(int in_wheels=4){wheels=in_wheels;}\nint get_wheels(){return wheels;}\n};\nvoid main()\n{\nvehicle unicyclel;\nvehicle unicycle2(3);\ncout<<\"Theunickele1has\"<\nclass vehicle{\nprotected:\nint wheels;\npublic:\nvehicle(int in_wheels=4){wheels=in_wheels;}\nint get_wheels(){return wheels;}\n};\nvoid main()\n{\nvehicle unicyclel;\nvehicle unicycle2(3);\ncout<<\"Theunickele1has\"<\nclass vehicle{\nprotected:\nint wheels;\npublic:\nvehicle(int in_wheels=4){wheels=in_wheels;}\nint get_wheels(){return wheels;}\n};\nvoid main()\n{\nvehicle unicyclel;\nvehicle unicycle2(3);\ncout<<\"Theunickele1has\"<